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Question #71b91 - Socratic
Since water is in excess, "67.7 g MgO" are needed to produce "98.0 g Mg(OH)"_2. Balanced equation "MgO(s) + H"_2"O(l)"rarr"Mg(OH)"_2("s")" Moles magnesium hydroxide Start with the given mass of "Mg(OH)"_2 and convert it to moles by dividing by its molar mass ("58.319 g/mol"). Since molar mass is a fraction, "g"/"mol", we can divide by multiplying by the reciprocal of the molar mass, "mol"/"g ...