How much zeros has the number $1000!$ at the end?
May 13, 2014 · 1 If a number ends with n n zeros than it is divisible by 10n 10 n, that is 2n5n 2 n 5 n. A factorial clearly has more 2 2 s than 5 5 s in its factorization so you only need to count …
probability - 1/1000 chance of a reaction. If you do the action …
A hypothetical example: You have a 1/1000 chance of being hit by a bus when crossing the street. However, if you perform the action of crossing the street 1000 times, then your chance …
algebra precalculus - Which is greater: $1000^ {1000}$ or $1001
The way you're getting your bounds isn't a useful way to do things. You've picked the two very smallest terms of the expression to add together; on the other end of the binomial expansion, …
algebra precalculus - Multiple-choice: sum of primes below $1000 ...
Jan 30, 2017 · Given that there are $168$ primes below $1000$. Then the sum of all primes below 1000 is (a) $11555$ (b) $76127$ (c) $57298$ (d) $81722$ My attempt to solve it: We …
Why is 1 cubic meter 1000 liters? - Mathematics Stack Exchange
Mar 7, 2015 · 0 Can anyone explain why $1\ \mathrm {m}^3$ is $1000$ liters? I just don't get it. 1 cubic meter is $1\times 1\times1$ meter. A cube. It has units $\mathrm {m}^3$. A liter is liquid …
terminology - What do you call numbers such as $100, 200, 500, …
What do you call numbers such as $100, 200, 500, 1000, 10000, 50000$ as opposed to $370, 14, 4500, 59000$ Ask Question Asked 13 years, 11 months ago Modified 9 years, 7 months ago
Last two digits of $2^ {1000}$ via Chinese Remainder Theorem?
For the congruence modulo $4$ you don't even need to invoke Euler's Theorem; you can just note that since $2^2\equiv 0\pmod {4}$, then $2^ {1000}\equiv 0 \pmod {4}$.
calculus - Optimization Problem. Find Smallest Perimeter of a …
Nov 14, 2018 · 5 QUESTION Find the dimensions of a rectangle with area $1000$ m $^2$ whose perimeter is as small as possible. MY WORK
definition - What is the smallest binary number of $4$ bit? Is it ...
Sep 29, 2024 · In pure math, the correct answer is $ (1000)_2$. Here's why. Firstly, we have to understand that the leading zeros at any number system has no value likewise decimal. Let's …
For sufficiently large $n$, Which number is bigger, $2^n$ or …
Dec 6, 2018 · How do I determine which number is bigger as $n$ gets sufficiently large, $2^n$ or $n^ {1000}$? It seems to me it is a limit problem so I tried to tackle it that way.