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  1. Palak Chaturvedi on Socratic

    i m a student of 15 yrs ...... ;who loves to learn, read and explore. My hobby is learning new facts . I am in 12 standard.

  2. Question #e4341 - Socratic

    Possibly yes, possibly not quite - read on for more. Hello Luz, You have 4 cups, which is 1 quart, so you have 0.25 gallons. But, there are two different measurement systems that use the term …

  3. Question #d3d51 - Socratic

    Explanation: Every time you happen to find an inappropriate answer, you can flag it for abuse or spam by clicking on that Suggest Improvements menu located right under the answer, and …

  4. Question #c7952 - Socratic

    44.009 "amu" To calculate the mass of one individual molecule of "CO"_2, we need to Multiply the atomic mass of carbon by however many carbon atoms are in the compound (1) Multiply the …

  5. Question #a4ebb - Socratic

    UPDATE As of July 14, 2016, the Socratic app is available in the app store! Install the app here Read about how it works Download it and let us know what you think! Original post: Yes, we …

  6. How to make Procedure Text? + Example - Socratic

    Jan 11, 2018 · See below for some ideas: Have you ever read an instruction manual or directions on how to assemble something?

  7. Please read and help me with this problem - Socratic

    Jan 31, 2018 · dy/dx=-1/x^2 Given - f(x)=1/x y=1/x The function can be written as - y=x^(-1) dy/dx=(-1).x^(-1-1) dy/dx=-x^(-2) dy/dx=-1/x^2

  8. Question #30c66 - Socratic

    We call 'c_v' the specific heat because it is the heat capacity of a substance divided by its mass, and all “specific” properties are properties per unit mass, or mass-specific properties. This can …

  9. Question #eb034 - Socratic

    You may have read how the massive earth quake Japan in 2011 actually shortened the length of the day by 2 milliseconds (aprox.). In the case of El Nino we have a large amount of warm …

  10. Question #9cbb8 - Socratic

    (d theta)/(dt) = 37/20 You were on the correct track with your setup on number 8, but when you took the derivative of the y/z term on the right side with respect to time t, you did not use the …